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Chemistry [sumone help me please :(]

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0.250g of phthalic acid is dissolved in 40.00cm^3 of 0.100 mol dm^-3 NaOH. It requires 11.80 cubic centimeters of 0.100 mol\dm^-3 HCL fo neutralisation( to phenolphthalein) The mole ratio in which phthalic acid reacts with sodium hydroxide ihn 1:2

(a) Calculate the moles of excess NaOH reacted with HCL
(b)Calculate the moles of phthalic acid used
(c) Calculate the molecular mass of phthalic acid

  • Chemistry [sumone help me please :(] - ,

    See your other post.

  • Chemistry [sumone help me please :(] - ,

    0.250 g of phthalic acid is dissolved in 40.00 cm3 of 0.100 mol dm-3 NaOH. It
    requires 11.80 cm3 of 0.100 mol dm-3 HCl for neutralisation (to
    phenolphthalein). The mole ratio in which phthalic acid reacts with sodium
    hydroxide is 1:2.

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