physics
posted by smarth .
In an 8.00 race, one runner runs at a steady 11.8 and another runs at 14.5 .How far from the finish line is the slower runner when the faster runner finishes the race?

Can't work without units.

A toy train is pushed forward and released at = 3.5 m with a speed of 1.0m/s . It rolls at a steady speed for 1.2s , then one wheel begins to stick. The train comes to a stop 3.4m from the point at which it was released.What is the train's acceleration after its wheel begins to stick?

and the other question is
km/h the units i mean
so the question is
in an 8.00km race, one runner runs at a steady 11.8km/h and another runs at 14.5km/h .How far from the finish line is the slower runner when the faster runner finishes the race? 
relative distance= relative velocity*time
= (14.511.8)km/hr * time
but time= 8km/14.5(km/hr)= 8/14.5 hr
relative distance= (above)*8/14.5 km 
im sorry bob but i don't get it :(
i don't understand what you mean