Calculate the number of grams of Fe found when 0.400kg of Fe2O3 reacts
280 g
To calculate the number of grams of Fe found when 0.400 kg of Fe2O3 reacts, we will need to use the stoichiometry of the reaction.
The balanced chemical equation for the reaction of Fe2O3 and Fe is:
Fe2O3 + 3 Fe → 2 Fe3O4
From the balanced equation, we can see that 1 mole of Fe2O3 reacts with 3 moles of Fe to produce 2 moles of Fe3O4.
First, we need to convert the mass of Fe2O3 from kg to grams.
1 kg is equal to 1000 grams, so 0.400 kg is equal to 0.400 x 1000 = 400 grams.
Next, we need to convert the mass of Fe2O3 to moles. To do this, we need the molar mass of Fe2O3, which is calculated by adding up the atomic masses of each element in the compound:
Fe2O3:
2(Fe) + 3(O) = 2(55.845 g/mol) + 3(16.00 g/mol) = 159.69 g/mol
Now we can convert the mass of Fe2O3 to moles:
moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3
= 400 g / 159.69 g/mol
= 2.506 moles of Fe2O3
According to the stoichiometry of the balanced equation, 1 mole of Fe2O3 reacts with 3 moles of Fe. So, we can now calculate the moles of Fe that will be produced:
moles of Fe = 3 moles of Fe2O3 x (1 mole of Fe / 1 mole of Fe2O3)
= 3 moles of Fe2O3
Finally, we can convert the moles of Fe to grams using the molar mass of Fe, which is 55.845 g/mol:
grams of Fe = moles of Fe x molar mass of Fe
= 3 moles of Fe x 55.845 g/mol
= 167.535 grams of Fe
Therefore, when 0.400 kg of Fe2O3 reacts, the number of grams of Fe produced is approximately 167.535 grams.
To calculate the number of grams of Fe found when 0.400 kg of Fe2O3 (iron(III) oxide) reacts, you need to use stoichiometry and the molecular formula of Fe2O3.
The balanced chemical equation for the reaction between Fe2O3 and Fe is:
Fe2O3 + 3Fe → 2Fe3O4
From this equation, you can see that 1 mole of Fe2O3 reacts with 3 moles of Fe, and the molar mass of Fe2O3 is 159.69 g/mol.
Step 1: Convert the mass of Fe2O3 to moles.
The molar mass of Fe2O3 is 159.69 g/mol.
Moles of Fe2O3 = Mass (g) / Molar mass (g/mol)
Moles of Fe2O3 = 0.400 kg * 1000 g/kg / 159.69 g/mol
Step 2: Use the mole ratio to determine moles of Fe.
From the balanced equation, the mole ratio between Fe2O3 and Fe is 1:3.
Moles of Fe = Moles of Fe2O3 * (3 moles of Fe / 1 mole of Fe2O3)
Step 3: Convert moles of Fe to grams.
The molar mass of Fe is 55.85 g/mol.
Mass of Fe = Moles of Fe * Molar mass of Fe
So, to calculate the number of grams of Fe found when 0.400 kg of Fe2O3 reacts, follow these steps:
1. Moles of Fe2O3 = 0.400 kg * 1000 g/kg / 159.69 g/mol
2. Moles of Fe = Moles of Fe2O3 * (3 moles of Fe / 1 mole of Fe2O3)
3. Mass of Fe = Moles of Fe * Molar mass of Fe
Performing these calculations will give you the number of grams of Fe produced.