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April 18, 2015

Posted by **Anonymous** on Tuesday, September 20, 2011 at 8:16pm.

I tried doing this, and I got 1.16 or something :S How exactly do I do this? Please tell me what formula to use. I was using the Sn = a(rn-1)/r-1

- Calculus -
**MathMate**, Wednesday, September 21, 2011 at 8:20pmThe geometric series up to the nth term is generally represented by the formula:

S(n)=a + ar + ar^2 + ar^3 .... + ar^(n-1)

Therefore

S(1)=a=0.7

S(2)=a+ar=a(1+r)=0.7*(1+2)

Therefore r=2

The formula for calculating the first n terms is

S(n)=a(r^n-1)/(r-1)

for n=12,

=0.7*(2^12-1)/(2-1)

You calculator should tell you that S(12) is below 3000.

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