can anyone show me the steps to convert to scinctific notation of these two problems:


.000316 which the answer is 3.16x10^-4

and 0.000517 which the answer is 5.17x10^-4

1. Move decimal point to get a single

digit number that is always equal to or
greater than 1, but less than 10.
Mathematically: 1<= N <10. In your case N = 3.16 for the 1st problem.

2. Count the number of places you moved the decimal point to get scientific notation. The number is 4 and it is your exponent. The exponent is negative, because you have to move
the decimal point to the left to return to Standard Form.

I hope this helps.

Certainly! Here are the steps to convert the given numbers into scientific notation:

1. For the number .000316:
- Start by counting the number of decimal places you need to move to the right to make the number between 1 and 10.
- In this case, you need to move the decimal point 4 places to the right: 0.000316 becomes 3.16.
- Now write this new number (3.16) as a coefficient, followed by multiplying it with 10 raised to the power of the number of places you moved the decimal point.
- Since you moved the decimal point 4 places to the right, your exponent will be -4.
- Therefore, the scientific notation representation for 0.000316 is 3.16 x 10^-4.

2. For the number 0.000517:
- Similar to the previous step, count the number of decimal places you need to move to the right to make the number between 1 and 10.
- In this case, you need to move the decimal point 4 places to the right: 0.000517 becomes 5.17.
- Write this number (5.17) as a coefficient, followed by multiplying it with 10 raised to the power of the number of places you moved the decimal point.
- Since you moved the decimal point 4 places to the right, the exponent will be -4.
- Hence, the scientific notation representation for 0.000517 is 5.17 x 10^-4.

Remember, to convert a number to scientific notation, you need to move the decimal point to make the number between 1 and 10, and then express it as a coefficient multiplied by 10 raised to a certain power.