precalculus
posted by natalie .
Could someone please help me with this problem?
square root of (2x+1) 5 = 8
I think I take the 5 and add it to the 8 and then I have
square root of (2x+1) = 13
then do I square both sides and end up with 2x+1 = 13^2
2x+1=169
2x+11=1691
2x=168
x=84 am I even close on this?

The best way to check is to substitute your answer back into the equation.
SQRT(2x+1)5=8
SQRT( (2*84)+1)5=8
SQRT(168+1)5=8
SQRT(169)5=8
13  5 = 8
8 = 8
You are correct!