The height in feet of a ball t seconds after it is thrown upward is given by height = -12t squared+87t +8 find the height of the ball 2 seconds after it has been released
h = -12*2^2 + 87*2 + 8 = 134 Ft.
To find the height of the ball 2 seconds after it has been released, we need to substitute t = 2 into the given equation and solve for height.
The equation for the height of the ball is:
height = -12t^2 + 87t + 8
Substituting t = 2:
height = -12(2)^2 + 87(2) + 8
height = -12 * 4 + 87 * 2 + 8
height = -48 + 174 + 8
height = 134 + 8
height = 142 feet
Therefore, the height of the ball 2 seconds after it has been released is 142 feet.
To find the height of the ball 2 seconds after it has been released, you can substitute t = 2 into the given equation and solve for the height.
The formula for the height of the ball at time t is given as:
height = -12t^2 + 87t + 8
We can substitute t = 2 into this equation:
height = -12(2)^2 + 87(2) + 8
Now, let's simplify the equation:
height = -12(4) + 87(2) + 8
= -48 + 174 + 8
= 134 feet
Therefore, the height of the ball 2 seconds after it has been released is 134 feet.