April 20, 2014

Homework Help: Calculus

Posted by Hannah on Tuesday, September 20, 2011 at 11:47am.

2sin(2theta) + sqrt(3) = 0
interval (0,2pi)

How do I solve this? I thought about maybe subtracting the sqrt(3) from both sides, so that i would have
2sin(2theta) = -sqrt(3)

Then maybe dividing by two?

sin(2theta) = -sqrt(3)/2

Am I doing anything right here? It's been a long time since I've worked with Trig, so I'm not sure . . .

Answer this Question

First Name:
School Subject:

Related Questions

Calculus - What is the integral of 1-tan^2theta from 0 to pi/3? Using the ...
Math! - Solve the equation on the interval 0<theta<2pi -tan(2theta)+2sin(...
Math - Can I please get some help on these questions: 1. How many solutions does...
Precalculus with Trigonometry - What values of theta between 0 and 2pi solve the...
MATH - Please help me with these problems. Work and answer is appreciated! :) ...
college - Trig help... equation on the interval [0,2pi]? 2sin^2(x)=sin(x)
calculus - Find circumference of the circle r=2acos theta. s= Int (0 to 2pi) of ...
Trig - 2sin^2(x) = 2 + cos(x) interval [0,2pi) How do I solve this? Help would ...
Precalculus - 2sin^2x+3cosx=3 find all solutions in the interval [0,2pi]
trig - slove the equation exactly over the interval [0, 2pi) sinx=1-2sin^2x