February 25, 2017

Homework Help: Calculus

Posted by Hannah on Tuesday, September 20, 2011 at 11:47am.

2sin(2theta) + sqrt(3) = 0
interval (0,2pi)

How do I solve this? I thought about maybe subtracting the sqrt(3) from both sides, so that i would have
2sin(2theta) = -sqrt(3)

Then maybe dividing by two?

sin(2theta) = -sqrt(3)/2

Am I doing anything right here? It's been a long time since I've worked with Trig, so I'm not sure . . .

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