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October 31, 2014

October 31, 2014

Posted by **Ja'Terra** on Tuesday, September 20, 2011 at 9:42am.

of a table that is 1.2 m high, and it strikes the

floor at a point 1.11 m from the base of the

table.

The acceleration of gravity is 9.8 m/s2 .

What is the initial speed of the ball?

Answer in units of m/s

- physics -
**drwls**, Tuesday, September 20, 2011 at 9:48amUsing the height H of the table, compute the time t required to hit the ground.

t = sqrt(2H/g)= 0.495 s

Initial speed =

= horizontal V component = (1.11 m)/t

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