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Posted by on Tuesday, September 20, 2011 at 8:43am.

Suppose the function G(t) represents a test grade (out of 100 points) as a function of hours studied. If
G(t)=-0.046t^3+0.915t^2+38.005 points, what is (dG/dt)when t=4? Round your answer to the nearest point per hour.


a. 50 points per hour

b. 3 points per hour

c. 5 points per hour

d. 7 points per hour

e. 20 points per hour

  • calculus - , Tuesday, September 20, 2011 at 8:48am

    Your umpteen posts have been removed.

    Once you write up WHAT YOU THINK, please re-post, and someone here will be happy to comment.

  • calculus - , Tuesday, September 20, 2011 at 8:52am

    WHY ARE YOU DELETING MY POSTS?

  • calculus - , Tuesday, September 20, 2011 at 9:00am

    To quote one of our very good math and science tutors: "You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which your thoughts are included."

  • calculus - , Tuesday, September 20, 2011 at 9:14am

    Derivative of t ^ 3 = 3 * t ^ 2

    Derivative of t ^ 2 = 2 * t

    Derivative of 38.005 = 0

    dG / dt = - 0.046 * 3 * t ^ 2 + 0.915 * 2 t + 0 = - 0.138 * t ^ 2 + 1.83 * t

    When t = 4

    then :

    dG / dt = - 0.138 * 4 ^ 2 + 1.83 * 4

    dG / dt = - 0.138 * 16 + 7 . 32

    dG / dt = - 2.208 + 7.32

    dG / dt = 5.112


    Rounded to the nearest point per hour :

    dG / dt = 5 points per hour

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