Posted by **Ronald** on Monday, September 19, 2011 at 11:55pm.

A home run is hit such a way that the baseball just clears a wall 30 m high located 117 m from home plate. The ball is hit at an angle of 40 degrees to the horizontal, and air resistance is negligible. Assume the ball is hit at a height of 2 m above the ground. The acceleration of gravity is 9.8 m/s^2.

What is the initial speed of the ball?

Answer in units of m/s

- Physics -
**drwls**, Tuesday, September 20, 2011 at 4:18am
You need to solve two simultaneous equations for the time of flight (T) and initial velocity, Vo.

Vo cos40 T = 117 meters

or

Vo*T = 152.7 m,

and

2 + Vo sin40 T- (g/2) T^2 = 30 meters

or

0.6428 Vo*T - 4.9 T^2 = 28

Solve for T first, then Vo

98.17 -4.9 T^2 = 28

T = 3.99 s

etc.

- Physics -
**Ivan**, Wednesday, October 14, 2015 at 11:31pm
Vi=60m/s

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