Posted by denise on .
once again I am not getting this.
assume that the population of heights of male college students is normally distibuted with a mean of 69.09 and standard deviation of 4.71. A random sample of 92 heights is obtained. find the mean and standard error of the x distribution.
find P(x>68.5)

statistics 
PsyDAG,
SEm = SD/√n
Best guess at the mean is the population mean.
Z = (scoremean)/SEm
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (P) related to the Z score.