calculus
posted by elise on .
identify the type of curve and sketch the graph of y22x+6y+5=0

Assuming y2 means y^2, then we have a parabola, opening to the right:
2x = y^2 + 6y + 5
= (y+1)(y+5)
So it has zeroes at y=1, y=5, axis of symmetry at y = 3, vertex at (2,3).