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August 29, 2014

August 29, 2014

Posted by **elise** on Monday, September 19, 2011 at 7:11pm.

- calculus -
**Steve**, Wednesday, September 21, 2011 at 1:49pmAssuming y2 means y^2, then we have a parabola, opening to the right:

2x = y^2 + 6y + 5

= (y+1)(y+5)

So it has zeroes at y=-1, y=-5, axis of symmetry at y = -3, vertex at (-2,-3).

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