Posted by elise on Monday, September 19, 2011 at 7:11pm.
Assuming y2 means y^2, then we have a parabola, opening to the right:
2x = y^2 + 6y + 5
= (y+1)(y+5)
So it has zeroes at y=-1, y=-5, axis of symmetry at y = -3, vertex at (-2,-3).
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