the perimiter of a triangle is 122cm. If the lengths of the sides of the triangle are(3x-1)cm, (4x+2)cm and (2x-5), what is the lenght of the longest
(3x-1) + (4x+2) + (2x-5) = 122
Combine like terms.
9x - 4 = 122
Solve for x and then evaluate each of the three sides.