Posted by Matt on Monday, September 19, 2011 at 4:27pm.
∫(6x^2 + 12x^(3/2) +4x+9]/√x)
= ∫ 6x^(3/2) + 12x + 4x^(1/2) + 9x^(-1/2) dx
= (12/5)x^(5/2) = 6x^2 + (8/3)x^(3/2) + 18x^(1/2) + c
∫ (12sinx + 4tanx) dx
= ∫( 12sinx + 4 sinx/cosx) dx
= -12cosx - 4ln(cosx) + c
∫ (x^7) e^(x^8) dx
= (1/8) e^(x^8) + c
Related Questions
Calc BC - 1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2...
Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...
calculus - Evaluate the indefinite integral. integral of 4e^(4x)sin[e^(4x)]dx
trig integration - s- integral endpoints are 0 and pi/2 i need to find the ...
calculus - Evaluate the indefinite integral. integral of 8 sin^4 x cos x dx
Calc - Evaluate the following indefinite integral integral of the funtion (x^3...
calculus - evaluate the indefinite integral integral sign [8/(x ln(1x))] dx...
calculus - evaluate the indefinite integral integral sign [8/x ln(1x)] dx = +c
Math - 1. Evaluate the indefinite integral integral symbol[6x5+2sec(x) tan(x)]dx...
Calculus - Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of...
For Further Reading