A point charge of 2.4 μC is located at

the center of a spherical shell of radius 17 cm, which has a charge −2.4 μC uniformly distributed on its surface. Given:
ke = 8.98755 × 109 Nm2/C2 .

a)Find the electric field for all points outside the spherical shell.

b)Find the electric field for a point inside the shell a distance 9 cm from the center.

The answer for b is not zero, btw.

a> charge enclosed is zero, E is zero. Gauss Law.

b. the E is due to the center charge ONLY (Gauss Law) E=kq/.09^2

For a), we're looking at outside of the shell which is not enclosed in the spherical shell.

A -7 nC point charge is located at the centre of conducing spherical shell.The shell has inner raduis 2m and outer raduis 4m and a charge of + 6 nC

Calculate the charge on the sphere outer surface ?

•A + 9.0 nC point charge is located in the center of a thick conducting spherical shell. The shell has an inner radius of 1.0 m, an outer radius of 1.4 m, and a charge of -5.0 nC. What is the magnitude of the electric field at r = 0.5 m?

To find the electric field for all points outside the spherical shell, we can use the principle of superposition. The total electric field at any point outside the shell is the sum of the electric fields due to the point charge at the center and the uniformly distributed charge on the surface.

a) Electric field for all points outside the spherical shell:

1. Electric field due to the point charge at the center:
The electric field at a point outside a charged sphere is given by Coulomb's Law:
E1 = ke * (q1 / r1^2)
where ke is the electrostatic constant (8.98755 × 10^9 Nm^2/C^2), q1 is the charge of the point charge (2.4 μC = 2.4 × 10^-6 C), and r1 is the distance from the point charge to the point where we want to find the electric field.

In this case, the point charge is at the center of the spherical shell, so the distance from the point charge to any point outside the shell is equal to the radius of the shell (17 cm = 0.17 m).
E1 = ke * (q1 / r1^2)
E1 = (8.98755 × 10^9 Nm^2/C^2) * (2.4 × 10^-6 C / (0.17 m)^2)

2. Electric field due to the uniformly distributed charge on the surface:
The electric field at any point outside a uniformly charged spherical shell is zero. This is because the electric fields due to the positive and negative charges cancel out, resulting in a net electric field of zero.

Therefore, the total electric field for all points outside the spherical shell is simply the electric field due to the point charge at the center:
E_total = E1

b) Electric field for a point inside the shell, 9 cm from the center:

To find the electric field for a point inside the shell, we again use the principle of superposition. We need to consider the electric field due to the point charge at the center and the electric field due to the charged shell.

1. Electric field due to the point charge at the center:
The electric field at any point inside the shell due to the point charge at the center can be found using Coulomb's Law as explained earlier.

2. Electric field due to the uniformly distributed charged shell:
To find the electric field due to the charged shell, we can use Gauss's Law. Gauss's Law states that the electric field inside a conducting shell is zero. This also applies to a uniformly charged shell since the conducting shell acts as a Faraday cage.

Therefore, the electric field at a point inside the shell, 9 cm from the center, is simply the electric field due to the point charge at the center. It is not zero.

To calculate the electric field specifically at a point 9 cm from the center, you can use the same formula as in part a) but with a different distance:
E2 = ke * (q1 / r2^2)
where r2 is the distance from the point charge to the point inside the shell (9 cm = 0.09 m).

E2 = (8.98755 × 10^9 Nm^2/C^2) * (2.4 × 10^-6 C / (0.09 m)^2)

Substitute the value of r2 and calculate E2 to find the electric field at a point 9 cm from the center inside the shell.