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Physics

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A car initially moving at 15 m/s accelerates at 4.5 m/s2 over a distance of 10 m. Find the final velocity?

  • Physics - ,

    Let the initial velocity be V1 = 15 m/s and the final velocity be V2 (unknown).

    Since F = M a is the accelerating force and the work done is
    W = F*X,

    K.E. change = (M/2)[V2^2 - V1^2] = M*a*X
    M cancels out.
    V^2^2 - V1^2 = 2 a X

    Solve for V2.

    There is another way to derive the same equation without using the mass and force.

    Travel time = T = X/(avg velocity)
    T = 2X/(V1 +V2)

    V2 -V1 = a*T = 2 a X/(V1 + V2)
    V2^2 - V1^2 = 2 a X

  • Physics - ,

    t=10m/15m.s
    =2/3s.

    V=u+a¤t
    v=(15m/s)+(4.5m/s2)(2/3sec)
    v=18m/s

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