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April 16, 2014

April 16, 2014

Posted by **Harmony** on Sunday, September 18, 2011 at 10:31pm.

- Physics -
**drwls**, Monday, September 19, 2011 at 9:14amLet the initial velocity be V1 = 15 m/s and the final velocity be V2 (unknown).

Since F = M a is the accelerating force and the work done is

W = F*X,

K.E. change = (M/2)[V2^2 - V1^2] = M*a*X

M cancels out.

V^2^2 - V1^2 = 2 a X

Solve for V2.

There is another way to derive the same equation without using the mass and force.

Travel time = T = X/(avg velocity)

T = 2X/(V1 +V2)

V2 -V1 = a*T = 2 a X/(V1 + V2)

V2^2 - V1^2 = 2 a X

- Physics -
**Fleance Mhlari**, Friday, April 5, 2013 at 12:16amt=10m/15m.s

=2/3s.

V=u+a¤t

v=(15m/s)+(4.5m/s2)(2/3sec)

v=18m/s

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