Posted by Louis on Sunday, September 18, 2011 at 10:20pm.
Use PV = nRT and solve for n with the original mixture of Ne and Ar. Then use PV = nRT with P increased by 50% and solve for n.
n2 - n1 = moles N2 added.
n = grams/molar mass. Solve for grams.
Related Questions
Chem hw! - 1. What pressure would be needed to compress 25.1 mL of hydrogen at 1...
Chem hw! - 1. What pressure would be needed to compress 25.1 mL of hydrogen at 1...
sciencee - 1. What pressure would be needed to compress 25.1 mL of hydrogen at 1...
chemistry - a sample containing 1.50 mol neon gas has a volume of 8.00L.what is ...
Chemistry - A 1.30-L sample of argon gas is at 1.02 atm and 21.5 degrees Celsius...
Chemistry - Samples of Neon and helium are placed in separate containers ...
Chemistry - Ideal gas law question A 4.0 liter container has two gases inside, ...
physics - .10 mol of Argon gas is admitted to an evacuated 50cm cubed container ...
Chemistry - Three gases (8.00 of methane,CH4 , 18.0 of ethane,C2H6 , and an ...
Chemistry - what is the percent (m/m) of argon gas in a mixture containing 45.0 ...
For Further Reading