Posted by **Destiny** on Sunday, September 18, 2011 at 8:33pm.

1,Sovle using the substitution method. Show your work. If the system has no solution or an infinite number of solutions,state this.

-x - 3y = -20

5x + 3y =40

2 Sovle using the elimination method. Show your work. If the system has no solution or an infinite number of solutions, state this

-3x + 4y = 1

-6x + 6y = -3

and

-2x + 3y = -37.5

-4x + 0y = -24

- Algebra -
**Reiny**, Sunday, September 18, 2011 at 8:46pm
form the 2nd equation: 3y = 40-5x

sub into the first:

-x - (40-5x) = -20

-x - 40 + 5x = -20

4x = 20

x = 5

sub into 3y = 40-5x

3y = 40-25

3y =15y=5

so x=5, y=5

2nd problem:

-3x + 4y = 1

-6x + 6y = -3

multiply the first by -2 to get

6x - 8y = -2

add the 2nd

-6x + 6y = -3 to get

-2y = -5

y = 5/2

sub into original first

-3x + 4(5/2) = 1

-3x = 1 - 10

x = 3

for the last did you notice if you divide the 2nd equation by -4 you get the value of x ?

I will let you finish it.

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