Posted by Destiny on Sunday, September 18, 2011 at 8:33pm.
form the 2nd equation: 3y = 40-5x
sub into the first:
-x - (40-5x) = -20
-x - 40 + 5x = -20
4x = 20
x = 5
sub into 3y = 40-5x
3y = 40-25
3y =15y=5
so x=5, y=5
2nd problem:
-3x + 4y = 1
-6x + 6y = -3
multiply the first by -2 to get
6x - 8y = -2
add the 2nd
-6x + 6y = -3 to get
-2y = -5
y = 5/2
sub into original first
-3x + 4(5/2) = 1
-3x = 1 - 10
x = 3
for the last did you notice if you divide the 2nd equation by -4 you get the value of x ?
I will let you finish it.
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