Saturday

August 23, 2014

August 23, 2014

Posted by **Anonymous** on Sunday, September 18, 2011 at 8:00pm.

How do I do this?

- Calculus -
**Reiny**, Sunday, September 18, 2011 at 8:04pmlooks like a geometric series where

a = -6 and r = 2

Term(n) = a(r^n - 1)/(r-1), where n is the number of terms

-378 = -6(2^n - 1)/(2-1)

63 = 2^n - 1

64 = 2^n

I know that 2^6 = 64

so n=6

so you need 6 terms.

- Calculus -
**Anonymous**, Sunday, September 18, 2011 at 8:10pmThank you so much, could you please help me with my other calculus posts.

**Related Questions**

Geometric series - The sum of the first five terms of a geometric series is 186 ...

FUNCTION 11..HELP! - The sun of the first five terms of a geometric series is ...

calculus infinate sums - how many terms of the series 1/(n*(ln(n)^8)) from n=2 ...

Math question - In an arithmetic series, the 15th term is 43 and the sum of the ...

Math - the sum of the first n terms of an arithmetic series is -51. the series ...

math - sorry for before it is my first time using this website and this is the ...

calculus - find the sum of the series from n=1 to infinity of 2^n/n! do I just ...

Calculus - If S1 = 0.7 and S2 = 2.1 in geometric series, what would the sum of ...

Calculus - - Reiny - If S1 = 0.7 and S2 = 2.1 in geometric series, what would ...

College Calculus (Binomial Series) - Expand f(x) = (x+x^2)/((1-x)^3) as a power ...