Posted by Anonymous on Sunday, September 18, 2011 at 8:00pm.
looks like a geometric series where
a = -6 and r = 2
Term(n) = a(r^n - 1)/(r-1), where n is the number of terms
-378 = -6(2^n - 1)/(2-1)
63 = 2^n - 1
64 = 2^n
I know that 2^6 = 64
so n=6
so you need 6 terms.
Thank you so much, could you please help me with my other calculus posts.
Related Questions
Math - the sum of the first n terms of an arithmetic series is -51. the series ...
Calculus - If S1 = 0.7 and S2 = 2.1 in geometric series, what would the sum of ...
math - Add the fractions 2/3, 3/8, and 5/12 and reduce your answer to lowest ...
Calculus - - Reiny - If S1 = 0.7 and S2 = 2.1 in geometric series, what would ...
Pre-Calculus - How many terms of the series -6+0+6+12+... are needed to yield a ...
Pre-Calculus - How many terms of the series 12+4+4/3+4/9+..., are needed to ...
calculus infinate sums - how many terms of the series 1/(n*(ln(n)^8)) from n=2 ...
Math....Please help I have a deadline for tonight! - Use the geometric sequence ...
Math - Is there a way to find the term number of a sum in an arithmetic series...
calculus - Find the sum of the series: 10 + 14 + 18 + 22 +...+138 and 6-12+24-48...
For Further Reading
