The specific heat of granite is 0.80 kJ/kg*Celsius. If 1.6 MJ of heat are added to a 100-kg granite of statue of James Prescott Joule that is origanlly at 18 degrees Celsius, what is the final temperture of the statue?
No one has been able to answer this one!!
To find the final temperature of the granite statue, we can use the equation:
Q = m * c * ΔT
Where:
Q is the heat energy added to the object (in joules),
m is the mass of the object (in kilograms),
c is the specific heat capacity of the material (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
First, let's convert the given heat energy of 1.6 MJ to joules:
1.6 MJ = 1.6 * 10^6 * 10^3 J = 1.6 * 10^9 J
Now we can rearrange the equation to solve for the change in temperature:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = (1.6 * 10^9 J) / (100 kg * 0.80 kJ/kg°C * 1000 J/kJ)
= 1.6 * 10^9 / (100 * 0.80 * 1000)
= 20°C
The change in temperature is 20 degrees Celsius. To find the final temperature, we add the change in temperature to the initial temperature of 18 degrees Celsius:
Final temperature = Initial temperature + ΔT
= 18°C + 20°C
= 38°C
Therefore, the final temperature of the granite statue will be 38 degrees Celsius.