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October 1, 2014

October 1, 2014

Posted by **Judy** on Sunday, September 18, 2011 at 5:52pm.

- Physics -
**drwls**, Sunday, September 18, 2011 at 8:52pmThe question should clarify that 3 km/h is the kayak velocity with respect to the water, which would be the velocity in still water, rowing at the same power level. It is NOT the actual velocity as seen from shore, whjich is higher, since the kayer is paddling downstream.

Vkl = Vkw + Vwl, where:

Vkl is the velocity of the kayak with respect to land;

Vkw is the velocity of the kayak with respect to the water;

Vwl is the velocity of the water with respect to the land (i.e, the stream velocity of + 4 km/h).

Solve for Vkl

4 + 3 = ___ ?

- Physics -
**Anon having exam tomorrow**, Monday, January 28, 2013 at 3:14pmIn this case you must use the Pyth. Theorem.

so: 3^2 + 4^2 = c^2

9+16=c^2

c^2=25

c=5m/s

the answer is correct, but I cannot ensure you that the way to do it is 100%ly correct

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