Saturday

December 20, 2014

December 20, 2014

Posted by **calculus** on Sunday, September 18, 2011 at 3:58pm.

- calculus -
**Steve**, Wednesday, September 21, 2011 at 4:17pmNot much calculus here, but here goes:

by definition

cos(cos^-1(x)) = x

cos^-1(cos(x)) = x

for x in suitable ranges. Now, for cos^-1(x) the function takes on principal values between 0 and π.

So, cos^-1(cos(15π/6)) = cos^-1(cos 5π/2) = cos^-1(0) = π/2.

**Answer this Question**

**Related Questions**

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Math - Calculus - The identity below is significant because it relates 3 ...

Calculus - which of the following integrals results from making the substitution...

Calculus - what is the limit n to infinite of cos1*cos(1/2)*cos(1/4)*cos(1/8)*...

Calculus - Evaluate (Integral) sin 4x cos^2 4x dx. A. Cos^3(4x)/3 + C B. -Cos^3(...

Calculus - Evaluate the integral sin4x cos^2 4x dx A. cos^3 4x/3 +C B. - cos^3 ...

Calculus (help Steve plz) - 1) if w = <-8, 15>, find ||w||? 2) which ...

calculus - pleaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaasw help can you pleaaaaase ...

Calculus - Let OP be any vector with direction angles theta, beta, and gama. ...

Math - verify the following identity used in calculus: cos(x+h)-cos(x)/h=cos(x)[...