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October 23, 2014

October 23, 2014

Posted by **Jane** on Sunday, September 18, 2011 at 1:56pm.

then dy/dx = ?

I've gotten to the point where i have

(5((3x^2)+ 5)^4)(4(x+2)^3)(6x), what do i do next? It's a multiple choice question anf this is not one of the answers listed. Any help would be appreciated. Thanks!

- AP Calculus AB -
**Reiny**, Sunday, September 18, 2011 at 4:56pmYour "first-line" derivative is

dy/dx = 5(3x^2 + 5)^4(6x)(x+2)^4 + 4(x+2)^3(3x^2+5)^5

= 2(x+2)^3(3x^2 + 5)^4 [ 15x(x+2) + 2(3x^2+5) ]

= 2(x+2)^3(3x^2 + 5)^4 [ 15x^2 + 30x + 6x^2 + 10 ]

= 2(x+2)^3(3x^2 + 5)^4 (21x^2 + 30x + 10)

- AP Calculus AB -
**Juliet**, Thursday, November 10, 2011 at 10:32pmThank you!

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