A bus that is traveling at 35.0 km/h, speeds up at a constant rate of 3.4 m/s2. What velocity does it reach 6.8 s later?
Vo = 35,000m/h * (1/3600)h/s = 9.72m/s.
Vf = Vo + at,
Vf = 9.72 + 3.4*6.8 = 32.84m/s.
To find the velocity of the bus after 6.8 seconds, we can use the equation of motion:
v = u + at
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Given:
u = 35.0 km/h (convert to m/s: 35.0 km/h * 1000 m/km * 1/3600 h/s = 9.72 m/s)
a = 3.4 m/s^2
t = 6.8 s
Substituting the values into the equation:
v = 9.72 m/s + (3.4 m/s^2) * (6.8 s)
Calculating:
v = 9.72 m/s + 23.12 m/s
v = 32.84 m/s