Posted by Sebastian on Sunday, September 18, 2011 at 12:28pm.
A pedestrian is running at his maximum speed of 6.0m/s to catch a bus stopped by a traffic light. When he is 25m away from the bus the light changes and the bus accelerates uniformly at 1.0m/s^2. Find either (a) how far he has to run to catch the bus or (b) his frustration distance(closest approach)
Physichs - Henry, Monday, September 19, 2011 at 8:20pm
a. d2 = d1 - 25,
6t = 0 + 0.5*1t^2 - 25,
6t - 0.5t^2 + 25 = 0,
-0.5t^2 + 6t + 25 = 0,
Uswe Quadratic Formula to find t:
t = 15.27s.
d = Vt = 6 * 15.27 = 91.6m.
Physichs - Anonymous, Thursday, September 17, 2015 at 10:40am