Posted by **Sebastian ** on Sunday, September 18, 2011 at 12:28pm.

A pedestrian is running at his maximum speed of 6.0m/s to catch a bus stopped by a traffic light. When he is 25m away from the bus the light changes and the bus accelerates uniformly at 1.0m/s^2. Find either (a) how far he has to run to catch the bus or (b) his frustration distance(closest approach)

- Physichs -
**Henry**, Monday, September 19, 2011 at 8:20pm
a. d2 = d1 - 25,

6t = 0 + 0.5*1t^2 - 25,

6t - 0.5t^2 + 25 = 0,

-0.5t^2 + 6t + 25 = 0,

Uswe Quadratic Formula to find t:

t = 15.27s.

d = Vt = 6 * 15.27 = 91.6m.

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