physics
posted by brandon on .
John kicks a soccer ball 12 m/s at an angle of 40.0 degrees above the horizontal. What is the ball's maximum height? Where does the ball land?

vertical velocity=12*sin40
consider the vertical: at the top, vertical velocity is zero
Vtop=Vinitialgt
0=12sin409.8 t solve for t, then solve for height
hf=12sin40*t 1/2 g t^2
Horizontal : total time in air is 2t.
distance=horizontal velocity*2t
= 12 cos40 * 2t