Posted by **brandon** on Sunday, September 18, 2011 at 11:36am.

John kicks a soccer ball 12 m/s at an angle of 40.0 degrees above the horizontal. What is the ball's maximum height? Where does the ball land?

- physics -
**bobpursley**, Sunday, September 18, 2011 at 12:27pm
vertical velocity=12*sin40

consider the vertical: at the top, vertical velocity is zero

Vtop=Vinitial-gt

0=12sin40-9.8 t solve for t, then solve for height

hf=12sin40*t -1/2 g t^2

Horizontal : total time in air is 2t.

distance=horizontal velocity*2t

= 12 cos40 * 2t

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