Posted by Gwendolyn on Saturday, September 17, 2011 at 8:52pm.
Find the vertex and the axis of symmetry for the parabola with the given equation y=5x230+47....

Algebra  Reiny, Saturday, September 17, 2011 at 10:44pm
I will assume you have a typo, with the first term 5x^2 and that the second term is 30x
the x of the vertex = b/(2a) = 30/(10) = 3
sub in x=3
y = 5(9)  30(3) + 47 = 2
vertex (3,2)
axis of symmetry : x = 3

Algebra  Gwendolyn, Sunday, September 18, 2011 at 10:10am
Thanks, I was getting something like 9
now I see what I did wrong.
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