Posted by **Gwendolyn** on Saturday, September 17, 2011 at 8:52pm.

Find the vertex and the axis of symmetry for the parabola with the given equation y=5x2-30+47....

- Algebra -
**Reiny**, Saturday, September 17, 2011 at 10:44pm
I will assume you have a typo, with the first term 5x^2 and that the second term is -30x

the x of the vertex = -b/(2a) = 30/(10) = 3

sub in x=3

y = 5(9) - 30(3) + 47 = 2

vertex (3,2)

axis of symmetry : x = 3

- Algebra -
**Gwendolyn**, Sunday, September 18, 2011 at 10:10am
Thanks, I was getting something like 9

now I see what I did wrong.

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