Posted by annne on Saturday, September 17, 2011 at 6:38pm.
Let us assume the shape of the parabolic path will be the same.
Then compare heights reached
v at top = 0 = Vi - g t
so t = Vi/g
so t on moon = 6 * t on earth
Right here you can say it will spend six times as long above soil so goes six times as far since horizontal velocity is the same for both and constant.
h = Vi t - (1/2) g t^2
hmoon = 6 Vi t -(1/2)(g/6)(36 t^2)
or
hmoon = 6 Vi t - 3 g t^2
but t = Vi/g
so h = Vi^2/g -.5 g Vi^2/g^2
h = .5 Vi^2/g
h moon = 3 Vi^2/g
so
height moon = 6 * height earth and distance moon = 6 times distance earth
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