Posted by Anonymous on .
A stone is thrown from a cliff top with a vertical velocity of 50 m/s and horizontal velocity of 20 m/s.
What is its resultant velocity?
At what angle above the horizontal is it thrown?
Xo = hor. = 20m/s.
Yo = ver. = 50m/s.
tanA = Yo / Xo = 50 / 20 = 2.5,
a = 68.2 Deg.
Vo = Xo / cosA = 20 / cos68.2 = 53.85m/s @ 68.2 deg.