Posted by **Wendy** on Friday, September 16, 2011 at 4:44pm.

2sin^2(x) = 2 + cos(x)

interval [0,2pi)

How do I solve this? Help would be greatly appreciated!

## Answer this Question

## Related Questions

- Math - Can I please get some help on these questions: 1. How many solutions does...
- Math Trig - Find all solutions on the interval [0,2pi] for the following: 2sin^2...
- trig - 2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3&#...
- Trig--check answer - Solve the equation of the interval (0, 2pi) cosx=sinx I ...
- trig - I need to find all solutions of the given equations for the indicated ...
- Calculus - 2sin(2theta) + sqrt(3) = 0 interval (0,2pi) How do I solve this? I ...
- trig - please help me with some questions I skipped on a review for our test ...
- Calculus help?? - I'm not sure how to solve this and help would be great! d/dx [...
- Math/Trig - Solve: sin x - 2sin x cos x = 0 for 0 is less than or equal to x is ...
- math (trig) - Find sin(x/2) if sin(x)= -0.4 and 3pi/2 < or equal to (x) < ...

More Related Questions