A piece of wire with mass per unit length 88 g/m runs horizontally at right angles to a horizontal magnetic field. A 6.5A current in the wire results in its being suspended against gravity.

What is the magnetic field strength?
Express your answer using two significant figures.
B = T

force= mg= ILB

mg/IL = B

m/L is given as .088kg/meter
g is well known
I is given.

To find the magnetic field strength, we can use the equation:

B = (mg) / (I * l)

Where:
B is the magnetic field strength
m is the mass per unit length of the wire (88 g/m)
g is the acceleration due to gravity (9.8 m/s^2)
I is the current through the wire (6.5 A)
l is the length of the wire (1 m)

Let's plug in the given values into the equation:

B = (88 g/m * 9.8 m/s^2) / (6.5 A * 1 m)

B = 1376 g m / (6.5 A)

Note that we need to convert the units of grams (g) to kilograms (kg). Since 1 g = 0.001 kg, we have:

B = (1376 g m / (6.5 A)) * (0.001 kg / 1 g)

B = 2.12 kg m / A

Finally, let's round the answer to two significant figures:

B ≈ 2.1 T

Therefore, the magnetic field strength is approximately 2.1 T (tesla).

To find the magnetic field strength (B), we can use the equation:

B = (m*g) / (I*L)

Where:
- B is the magnetic field strength
- m is the mass per unit length of the wire
- g is the acceleration due to gravity
- I is the current in the wire
- L is the length of the wire

Given values:
- m = 88 g/m
- I = 6.5 A

To find g, we can use the approximate value of 9.8 m/s^2.

To find L, we need additional information because it is not provided in the question. If you have the length of the wire, you can substitute it into the formula.

Use the equation F=IL X B that relates force on a current in a magnetic field.

Knowing the mass of the wire (.08)kg and the acceleration due to grav (9.8m/s^2) relate the two forces and solve for the variable B.

Because the cross product of L and B is 1 the relation is pretty simple.

(9.8)(.08)=5.8B