calculus
posted by Derrick on .
For what values of a and b that make the function f continuous everywhere.
f(x)={(x^24)/(x2) if x<2
ax^2bx18 if 2<x<3
10xa+b if x>3

There are three segments of functions, and two possibly discontinuous points, at x=2 and x=3.
Equate the adjacent segments to find the value of a and b that make the segments have the same values at x=2 and x=3.
Finally, check that the limits approaching from each side (2 and 2+, 3 and 3+) of the combined function are identical. They should be if the function is continuous.