Posted by mo on Friday, September 16, 2011 at 12:25pm.
ok i have a problem to work on in my new course, and i was wondering what i need to do to tackle it. the question is as follows:
An electron is projected with an initial velocity Vo=10^7m/s into the uniform field between the parallel plates "E". the direction of the field is vertically downward and the field is zero everywhere else except between plates. the electron enters the field at a point midway the plates. if the electron just misses the upper plate as it uses energy from the field, find the magnitude of the field "E"
are these the formulas needed
F = ma = qE
s = ut + 0.5 at^2
v = u + at
v^2 = u^2 + 2as
and what does ( a, u, and s) stand for?

physics  bobpursley, Friday, September 16, 2011 at 1:46pm
Eq= force= mass*acceleration
solve for the acceleration upward.
NOTE: the u above is initial velocity, in the direction of deflection, u is zero.
a is acceleration
s is distance. now back to the problem
*************************
I would like to know the measurements of the plates, ie separation, and the length of the plates along the originalpath. Is that given?

physics  Anonymous, Friday, September 16, 2011 at 1:49pm
the distance between the two plates is 1cm
and the lengeth of each plate is 2cm

physics  mo, Friday, September 16, 2011 at 2:01pm
the distance between the two plates is 1cm
and the lengeth of each plate is 2cm
so how do i get started

physics  bobpursley, Friday, September 16, 2011 at 4:40pm
Eq=mass*acceleration
so this is the acceleration toward the plate.
How long is it being accelerated?
lengthplate=V*t solve for time
So then we know that in the vertical acceleration between the plates.
distance moved=1/2 *.001m
but distance moved= 1/2 a t^2
set those equal, solve for a (you know time).
Now Eq=ma you know q, m, a solve for E
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