Need help with this problem Substitution
5x-3y=-11 (1)
3x+2y=1 (2)
Equation ( 2 )
3x + 2y = 1
2y = 1 -3 x Divide both sides with 2
y = 1 / 2 - 3x / 2
Equation ( 1 )
5x - 3y = -11
5x - 3 * ( 1 / 2 - 3x / 2 ) = -11
5x - 3 / 2 + 9x / 2 = -11
(Remark: 5 = 10 / 2 , 11 = 22 / 2)
10x / 2 + 9x / 2 = -22 / 2 + 3 / 2
19x / 2 = -19 / 2 Multipy both sides with 2
19x = -19 Divide both sides with 19
x = -1
y = 1 / 2 - 3x / 2
y = 1 / 2 - 3 * ( -1 ) / 2
y= 1 / 2 + 3 / 2
y = 4 / 2
y = 2
x = - 1 , y = 2