Posted by **Catherine** on Thursday, September 15, 2011 at 9:00pm.

Please help?

Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4) between x=0 and x=a, for a>0 (consider the area to be negative if the graph lies below the axis).

Find the formula for F(a).

- Calculus -
**Mgraph**, Thursday, September 15, 2011 at 9:12pm
We integrate by parts twice:

1)u=x^2, du=2xdx, dv=cos(x/4)dx, v=4sin(x/4)

2)u=8x, du=8dx, dv=sin(x/4)dx, v=-4cos(x/4)

The answer I have already sent.

- Calculus -
**Catherine**, Thursday, September 15, 2011 at 9:17pm
Yes, you are right Thanks, I just found it! =)

## Answer this Question

## Related Questions

- Calculus - Please help? Let F(a) be the area between the x-axis and the graph of...
- Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...
- Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...
- Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...
- calculus - The graph of f'(x) is shown for 0=< x =<10. The areas of the ...
- calculus(Lab) - Well, first graph the graph of f(x)=-1/10x^2 + 3 2. We are going...
- Algebra help! - I dont understand my problems that I am suppose to do. please ...
- Calculus - Consider the function x^2+x-4 Estimate the area between the graph and...
- Writing equation of a polynomial function - Can you help me with the following ...
- Calculus - The functions f and g are given by f(x)=√x and g(x)=6-x. Let R ...