Posted by Catherine on Thursday, September 15, 2011 at 9:00pm.
Please help?
Let F(a) be the area between the xaxis and the graph of y=x^2cos(x/4) between x=0 and x=a, for a>0 (consider the area to be negative if the graph lies below the axis).
Find the formula for F(a).

Calculus  Mgraph, Thursday, September 15, 2011 at 9:12pm
We integrate by parts twice:
1)u=x^2, du=2xdx, dv=cos(x/4)dx, v=4sin(x/4)
2)u=8x, du=8dx, dv=sin(x/4)dx, v=4cos(x/4)
The answer I have already sent.

Calculus  Catherine, Thursday, September 15, 2011 at 9:17pm
Yes, you are right Thanks, I just found it! =)
Answer This Question
Related Questions
 Calculus  Please help? Let F(a) be the area between the xaxis and the graph of...
 Calculus  Let F(a) be the area between the xaxis and the graph of y=x^2cos(x/4...
 Calculus  Let F(a) be the area between the xaxis and the graph of y=x^2cos(x/4...
 Calculus  Let F(a) be the area between the xaxis and the graph of y=x^2cos(x/4...
 calculus  The graph of f'(x) is shown for 0=< x =<10. The areas of the ...
 Functions, graphs  f(x)=(x+1)/(1+x^2) a) explain why the graph lies above the ...
 calculus(Lab)  Well, first graph the graph of f(x)=1/10x^2 + 3 2. We are going...
 Algebra help!  I don't understand my problems that I am suppose to do. please ...
 Calculus  Consider the function x^2+x4 Estimate the area between the graph and...
 Calculus  The functions f and g are given by f(x)=√x and g(x)=6x. Let R ...
More Related Questions