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September 16, 2014

September 16, 2014

Posted by **Catherine** on Thursday, September 15, 2011 at 9:00pm.

Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4) between x=0 and x=a, for a>0 (consider the area to be negative if the graph lies below the axis).

Find the formula for F(a).

- Calculus -
**Mgraph**, Thursday, September 15, 2011 at 9:12pmWe integrate by parts twice:

1)u=x^2, du=2xdx, dv=cos(x/4)dx, v=4sin(x/4)

2)u=8x, du=8dx, dv=sin(x/4)dx, v=-4cos(x/4)

The answer I have already sent.

- Calculus -
**Catherine**, Thursday, September 15, 2011 at 9:17pmYes, you are right Thanks, I just found it! =)

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