Wednesday

January 28, 2015

January 28, 2015

Posted by **Catherine** on Thursday, September 15, 2011 at 9:00pm.

Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4) between x=0 and x=a, for a>0 (consider the area to be negative if the graph lies below the axis).

Find the formula for F(a).

- Calculus -
**Mgraph**, Thursday, September 15, 2011 at 9:12pmWe integrate by parts twice:

1)u=x^2, du=2xdx, dv=cos(x/4)dx, v=4sin(x/4)

2)u=8x, du=8dx, dv=sin(x/4)dx, v=-4cos(x/4)

The answer I have already sent.

- Calculus -
**Catherine**, Thursday, September 15, 2011 at 9:17pmYes, you are right Thanks, I just found it! =)

**Answer this Question**

**Related Questions**

Calculus - Please help? Let F(a) be the area between the x-axis and the graph of...

Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...

Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...

Calculus - Let F(a) be the area between the x-axis and the graph of y=x^2cos(x/4...

calculus(Lab) - Well, first graph the graph of f(x)=-1/10x^2 + 3 2. We are going...

calculus - The graph of f'(x) is shown for 0=< x =<10. The areas of the ...

Calculus - Consider the function x^2+x-4 Estimate the area between the graph and...

calculus - Find the area between the graph of f and the x-axis over the interval...

Pre-Calc - Can anyone help with the following problem please...Thank u so much ...

calculus - consider the area enclosed between the curves f(x)=x^2 and g(x)=4x ...