Posted by **margaret** on Thursday, September 15, 2011 at 4:06pm.

A stone is thrown straight up from the ground with an initial speed of 30.5 m/s . At the same instant, a stone is dropped from a height of h meters above ground level. The two stones strike the ground simultaneously.Find the height h. gravity is 9.8 m/s2 .

Answer in units of m

The acceleration of

- physics -
**Henry**, Friday, September 16, 2011 at 8:08pm
t(up) = (Vf - Vo) / g,

t(up) = (0 - 30.5) / -9.8 = 3.11m.

t(dn) = t(up) = 3.11s.

T=t(up) + t(dn) = 3.11 + 3.11 = 6.22s =

Time in flight.

The 2 stones were in flight for the same period of time:

T1 = T2 = 6.22s.

h = Vo*t + 4.9t^2,

h = 0 + 4.9*(6.22)^2 = 189.6m.

- physics -
**Henry**, Friday, September 16, 2011 at 8:10pm
Post it.

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