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Math Help Please!!!

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A couple purchased a house and signed a mortgage contract for $110,000 to be paid in “every second week “ installments over 25 years, at 3.0 %. The contract stipulates that after 3 years the mortgage will be renegotiated at the new prevailing rate of interest. Calculate:
a) The every second week payment for the initial 3-year period
b) The outstanding principal after 3 years.
c) The new payment ( now, once a month )after the 3 years, at 4.5 %

NOTE: mortgages rates in Canada are always compounded twice a year.

  • Math Help Please!!! - ,

    first we must find the rate for the "every second week" period.
    let that rate be i
    (1+i)^26 = 1.015 , (semi-annual rate is 1.5%)
    1+i = 1.015^(1/26) = 1.000572803
    i = .000572803 ( I stored the full decimal in memory of calculator)

    then if P is the payment
    110000 = P[ 1 - 1.000572803^-650 ]/.000572803
    P = 202.73

    b) This continues for 3 years, or 78 payments
    Balance after 3 years
    = 110000(1.000572803)^78 - 202.73[ 1.000572803^78 - 1]/.000572803
    = 115024.61 - 16167.01
    = 98857.60

    c) Now we have to find the equivalent monthly rate for 4.5%
    let it be j
    (1+j)^6 = 1.0225
    j = .00371532
    new montly payment M , 22 years left or 264 payments
    98857.60 = M [1 - 1.00371532^-264]/.00371532
    M = 588.30 per month

    I suggest you check my "arithmetic" on this one.

  • LET'S TRY THIS AGAIN - ,

    Totally missed the part that our rates are assumed to be compounded semi-annually !!

    So we first have to find the equilavalent semi-annual rate equal to 3% compounded annually.
    let that rate be j
    (1+j)^2 = 1.03
    1+j = √1.03
    j = .014889157 (I stored that in calculator memory)

    Now we must find the rate for the "every second week" period.
    let that rate be i
    (1+i)^26 = 1.014889157 , (semi-annual rate is 1.014889157 %)
    same steps as above ...
    i = .0005686

    then if P is the payment
    110000 = P[ 1 - 1.0005686^-650 ]/.0005686
    P = 202.47

    b) This continues for 3 years, or 78 payments
    Balance after 3 years
    = 110000(1.0005686)^78 - 202.73[ 1.0005686^78 - 1]/.0005686
    = 114986.94 - 16143.68
    = 98843.26 ---> balance after 3 years (78 payments)

    c) Equivalent rate compounded semi-annual ...
    let that rate be k
    (1+k)^2 = 1.045
    k = .0022252415
    Now we have to find the equivalent monthly rate for the above rate
    let it be j
    (1+j)^6 = 1.0022252415
    j = .003674809
    new montly payment M , 22 years left or 264 payments
    98857.60 = M [1 - 1.003674809^-264]/.003674809
    M = 585.57 per month

  • Final correction - Math Help Please!!! - ,

    This is the problem when "cutting and pasting"
    It is so easy to miss a change that should be made

    2nd last line should say

    98843.26 = M [1 - 1.003674809^-264]/.003674809

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