Posted by Hel P. on Thursday, September 15, 2011 at 4:23am.
The precipate is Lead(II)iodide, hopefully, and you have .545grams lead iodide.
The easy way is to figure the number of moles that you have.
moles= massPbI2/molmassPbI2
Next, because the moles of Pb+2 ion is the same as the moles of PbI2 which was formed, then
Molarityoriginal= molesPb+2/.032
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