Posted by Lois on Wednesday, September 14, 2011 at 11:35pm.
let the "certain" speed be x mph
so time at the certain speed = 93/x
slower speed = x-5
time at slower speed = 19/(x-5)
so 93/x + 19/(x-5) = 3
times x(x-5)
93(x-5) + 19x = 3x(x-5)
93x - 465 + 19x = 3x^2 - 15x
3x^2 - 127x + 465 = 0
x = (127 ± √(10549)/6 = 38.28 or 4.045 mph
the "certain" speed of 4.045 mph would give us a negative speed for the second leg, so we have to reject that.
so that leaves us with a speed of 38.28 mph for the first part, and 33.28 mph for the second part of the trip.
(notice that 93/38.28 + 19/33.28 = 3)
Even though the answer fits the given data, the question is totally ridiculous.
I am an avid canoist and to be able to canoe at 38 mph is totally absurd.
Thank you so much for your help, and I would be interested in watching someone try to paddle a canoe or any boat that fast. Bet their arms would be very tired before they went 1/4 mile.
Related Questions
Math - During the first part of a trip, a canoeist travels 33 miles at a certain...
Algebra - Please HELP - During the first part of a trip a canoeist travels 49 ...
MAT117 - During the first part of a trip, a canoeist travels 68 miles at a ...
algebra - during the first part of a trip a canoeist travels 64 miles at a ...
algebra - During the first part of a trip a canoeist travels 71 miles at a ...
Algebra - During the first part of a trip a canoeist travels 49 miles at a ...
ALGEBRA - DURING THE FIRST PART OF A TRIP, A CANOEIST TRAVELS 35 MILES AT A ...
algebra - During the first part of a trip, a canoeist travels 69 miles at a ...
algebra 2 - during the first part of a trip, a canoeist travels 47 miles at a ...
Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...
For Further Reading