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October 31, 2014

October 31, 2014

Posted by **Lois** on Wednesday, September 14, 2011 at 11:35pm.

- math -
**Reiny**, Thursday, September 15, 2011 at 12:10amlet the "certain" speed be x mph

so time at the certain speed = 93/x

slower speed = x-5

time at slower speed = 19/(x-5)

so 93/x + 19/(x-5) = 3

times x(x-5)

93(x-5) + 19x = 3x(x-5)

93x - 465 + 19x = 3x^2 - 15x

3x^2 - 127x + 465 = 0

x = (127 ± √(10549)/6 = 38.28 or 4.045 mph

the "certain" speed of 4.045 mph would give us a negative speed for the second leg, so we have to reject that.

so that leaves us with a speed of 38.28 mph for the first part, and 33.28 mph for the second part of the trip.

(notice that 93/38.28 + 19/33.28 = 3)

Even though the answer fits the given data, the question is totally ridiculous.

I am an avid canoist and to be able to canoe at 38 mph is totally absurd.

- math -
**Lois**, Thursday, September 15, 2011 at 2:15amThank you so much for your help, and I would be interested in watching someone try to paddle a canoe or any boat that fast. Bet their arms would be very tired before they went 1/4 mile.

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