Posted by Sydney on .
Two children are playing on two trampolines. The first child can bounce 1.6 times higher than the second child. The initial speed up of the second child is 5.2 m/s.
(a) Find the maximum height the second child reaches.
(b) What is the initial speed of the first child?
(c) How long was the first child in the air?

Physics 
Brianna,
Yo= 0m
h=?
A=g=9.8m/s^2
Child A:
Voa= ?
Ya= 1.6h
Ta= ?
Child B:
Vob= 5.2 m/s
Yb= h
a) Vob^2 = 2AYb
Yb= Vob/2A
h= (5.2 m/s)^2/(2(9.8m/s^2))
h= 1.37m
b) Voa=?
Voa^2=2AYa
Voa= sqrt(2AYa)
Voa= sqrt(2(9.8m/s^2)(1.6(1.37)))
Voa= 6.55m/s
c) sorry but i can't figure out how to do c