posted by Sydney on .
Two children are playing on two trampolines. The first child can bounce 1.6 times higher than the second child. The initial speed up of the second child is 5.2 m/s.
(a) Find the maximum height the second child reaches.
(b) What is the initial speed of the first child?
(c) How long was the first child in the air?
Vob= 5.2 m/s
a) Vob^2 = 2AYb
h= (5.2 m/s)^2/(2(9.8m/s^2))
c) sorry but i can't figure out how to do c