Posted by Shayne on Wednesday, September 14, 2011 at 9:35pm.
dy/dx = 2x-7 which is the slope of the tangent.
so the normal must have a slope of -1/(2x-7) or 1/(7-2x)
but that is supposed to be parallel to x-3y=3
that is, a slope of 1/3
1/(7-2x) = 1/3
3 = 7-2x
2x = 4
x = 2
when x=2, y = 4-14+5 = -5
so the normal has equation
x - 3y = c
with (2,-5) on it, so
2 + 15 = c
equation of normal is
x - 3y = 15
check: at (2,-5) slope should be -3
dy/dx = 2(2)-7 = -3
My answer for the equation of the normal is correct!!
Related Questions
calculus: multivariable - Find the points on the hyperboloid x2 −y2 +...
math - Consider the parabola y = 7x - x2. (a) Find the slope of the tangent line...
calculus - Find an equation for the surface consisting of all points P(x, y, z) ...
calculus - If g(1) = 4 and g¢ (1) = − 2, find f ¢ (1), where...
calculus - Use the shell method to find the volume of the solid generated by ...
calculus - Consider the following. y = x2 − 9x x2 + 5x at (3, &#...
Calculus - find the parabola whose minimum is at (7,6) rather than the point ...
MATH - a parabola passes via the points (1.5,1) and (3,-5). given that the ...
math help & correction - Problem #1 Is this correct or wrong? Find the slope...
Math - If f(x)=3x^2-5x, find the f'(2) & use it to find an equation of ...
For Further Reading
