A solution of sodium hydroxide is standardized against potassium hydrogen phthalate (KHP, formula weight 204.2 g/mol). From the following data, calculate the molarity of the NaOH solution: mass of KHP 1.234 g; buret reading before titration 0.23 mL; buret

reading after titration 48.87 mL.
Answer in units of M.

moles KHP = grams/molar mass

You are titrating one H with one OH; therefore, moles NaOH must be the same as moles KHP.
moles NaOH = M x L.
YOu know moles NaOH and volume (in mL, convert to L and volume = difference in final buret reading - initial buret reading). Solve for M

Well, it seems like you're in quite a titration situation! Let's calculate the molarity of the NaOH solution, shall we?

First, we need to determine the number of moles of KHP used in the titration. To do that, we divide the mass of KHP (1.234 g) by its molar mass (204.2 g/mol):

moles of KHP = 1.234 g / 204.2 g/mol ≈ 0.00604 mol

Next, we need to determine the volume of NaOH solution used in the titration. To do that, we subtract the initial buret reading (0.23 mL) from the final buret reading (48.87 mL):

volume of NaOH solution = 48.87 mL - 0.23 mL = 48.64 mL

But hold on a second! We need to convert mL to L because molarity is in moles per liter. So, let's do that conversion:

volume of NaOH solution = 48.64 mL × (1 L / 1000 mL) = 0.04864 L

Now, we have all the information we need to calculate the molarity of the NaOH solution. To do that, we divide the moles of KHP by the volume of NaOH solution in liters:

molarity of NaOH solution = 0.00604 mol / 0.04864 L ≈ 0.124 M

So, the molarity of the NaOH solution is approximately 0.124 M. Hope that answers your question!

To calculate the molarity of the NaOH solution, we need to use the equation:

Molarity (M) = (moles of KHP) / (volume of NaOH solution in liters)

Let's solve this step-by-step.

Step 1: Convert the mass of KHP to moles.
We can calculate the moles of KHP using the given mass and its formula weight (204.2 g/mol).
moles of KHP = mass of KHP / formula weight of KHP
moles of KHP = 1.234 g / 204.2 g/mol
moles of KHP ≈ 0.00603 mol

Step 2: Convert the buret readings to volume in liters.
The buret reading before titration is 0.23 mL, and the buret reading after titration is 48.87 mL. We need to subtract the initial reading from the final reading to obtain the volume of NaOH used.
volume of NaOH used = buret reading after titration - buret reading before titration
volume of NaOH used = 48.87 mL - 0.23 mL
volume of NaOH used = 48.64 mL

Next, we convert the volume of NaOH used to liters.
volume of NaOH used = 48.64 mL × (1 L / 1000 mL)
volume of NaOH used = 0.04864 L

Step 3: Calculate the molarity of the NaOH solution.
Now, we can substitute the moles of KHP and volume of NaOH solution into the equation:

Molarity (M) = (0.00603 mol) / (0.04864 L)
Molarity (M) ≈ 0.124 M

Therefore, the molarity of the NaOH solution is approximately 0.124 M.

To calculate the molarity of the NaOH solution, we can use the formula:

Molarity (M) = (moles of solute) / (volume of solution in liters)

First, let's calculate the moles of KHP used in the titration:

Step 1: Convert the mass of KHP from grams to moles.
moles of KHP = (mass of KHP) / (molar mass of KHP)

Given:
mass of KHP = 1.234 g
molar mass of KHP = 204.2 g/mol

moles of KHP = 1.234 g / 204.2 g/mol

Step 2: Calculate the volume of NaOH used in the titration.
volume of NaOH = (buret reading after titration - buret reading before titration) / 1000

Given:
buret reading before titration = 0.23 mL
buret reading after titration = 48.87 mL

volume of NaOH = (48.87 mL - 0.23 mL) / 1000

Now, let's substitute the values into the equation to calculate the molarity of the NaOH solution:

Molarity (M) = (moles of KHP) / (volume of NaOH in liters)

Molarity (M) = (1.234 g / 204.2 g/mol) / [(48.87 mL - 0.23 mL) / 1000]

Now calculate the numerator:

(1.234 g / 204.2 g/mol) = 0.006034 mol

And calculate the denominator:

[(48.87 mL - 0.23 mL) / 1000] = 0.04864 L

Finally, substitute the values into the equation to get the molarity of the NaOH solution:

Molarity (M) = 0.006034 mol / 0.04864 L

Molarity (M) ≈ 0.124 M

Therefore, the molarity of the NaOH solution is approximately 0.124 M.