Posted by Brian on Wednesday, September 14, 2011 at 9:25pm.
Let M=1000. Which of the conditions is equivalent to f(x)= 1/((4x12)^2)>M?
a. absolute value of (x+3) is greater than or equal to .00158
b. absolute value of (x+3) is greater than or equal to .0553
c. absolute value of (x3) is less than .00791
d. absolute value of (x3) is less than .00158
e. absolute value of (x) is greater than .00395

calculus  Steve, Wednesday, September 21, 2011 at 4:59pm
We have
1/(4x12)^2 = 1/16(x3)^2 > 1000
(x3)^2 < 1/16000
x3 < 0.00791