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Posted by on Wednesday, September 14, 2011 at 9:25pm.

Let M=1000. Which of the conditions is equivalent to f(x)= 1/((4x-12)^2)>M?

a. absolute value of (x+3) is greater than or equal to .00158
b. absolute value of (x+3) is greater than or equal to .0553
c. absolute value of (x-3) is less than .00791
d. absolute value of (x-3) is less than .00158
e. absolute value of (x) is greater than .00395

  • calculus - , Wednesday, September 21, 2011 at 4:59pm

    We have

    1/(4x-12)^2 = 1/16(x-3)^2 > 1000

    (x-3)^2 < 1/16000
    |x-3| < 0.00791

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