Posted by **dan** on Wednesday, September 14, 2011 at 8:27pm.

a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?

- physics -
**Damon**, Wednesday, September 14, 2011 at 8:38pm
x = Vi t + (1/2) a t^2

125 = (25000/3600)(12) + .5 * a * 144

solve for a

then

v = Vi + a t

- physics -
**dan**, Wednesday, September 14, 2011 at 9:02pm
where did you get the 144

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**dan**, Wednesday, September 14, 2011 at 9:11pm
ok i get

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**dan**, Wednesday, September 14, 2011 at 9:18pm
correct me if im wrong solve for a = 102

and v = 1249

- physics -
**dan**, Wednesday, September 14, 2011 at 9:33pm
A = 51.15

V= 638.8

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