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Posted by **PLEASE HELP** on Wednesday, September 14, 2011 at 7:17pm.

- MATH HELP PLEASE -
**Lena**, Wednesday, September 14, 2011 at 7:22pmWell this is my thinking. The factors of 33 are as follows:

1 x 33

3 x 11

Therefore, you wouldn't be able to fill all 4 kennels if you used all the dogs. The only thing that makes sense to me is to not put one of the dogs in the kennel (which gives you 32 dogs):

4 x 8 = 32

So if you put 8 dogs per kennel, you have the same number of dogs in each kennel.

- MATH HELP PLEASE -
**Ken**, Wednesday, September 14, 2011 at 8:44pmonly use 3 of the available kennels?

- MATH HELP PLEASE -
**alex**, Wednesday, September 14, 2011 at 9:59pm8 remainder of 1

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