Posted by PLEASE HELP on Wednesday, September 14, 2011 at 7:17pm.
Well this is my thinking. The factors of 33 are as follows:
1 x 33
3 x 11
Therefore, you wouldn't be able to fill all 4 kennels if you used all the dogs. The only thing that makes sense to me is to not put one of the dogs in the kennel (which gives you 32 dogs):
4 x 8 = 32
So if you put 8 dogs per kennel, you have the same number of dogs in each kennel.
only use 3 of the available kennels?
8 remainder of 1
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