Post a New Question

Physics

posted by .

A cheetah can accelerate from rest to 25.9 m/s in 1.80 s. Assuming the acceleration is constant over the time interval, what is the magnitude of the acceleration of the cheetah?
What is the distance traveled by the cheetah in these 1.80 s?

  • Physics -

    a =(Vf - Vo) / t,
    a = (25.9 - 0) / 1.8 = 14.39m/s^2.

    b. d = Vo*t + 0.5*at^2,
    d = 0 + 0.5*14.39*(1.8)^2 = 23.3m.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question