posted by Wing on .
A cheetah can accelerate from rest to 25.9 m/s in 1.80 s. Assuming the acceleration is constant over the time interval, what is the magnitude of the acceleration of the cheetah?
What is the distance traveled by the cheetah in these 1.80 s?
a =(Vf - Vo) / t,
a = (25.9 - 0) / 1.8 = 14.39m/s^2.
b. d = Vo*t + 0.5*at^2,
d = 0 + 0.5*14.39*(1.8)^2 = 23.3m.