# Physics-can anyone check my work?

posted by
**Katie** on
.

A particle starts from the origin with velocity 2i m/s at t = 0 and moves in the xy plane with a varying acceleration given by 2 (sq root t) where is in meters per second squared and t is in seconds.

(a) Determine the velocity of the particle as a function of time.

So I calculated and got

v(t) = 2i + (4 (sq root t^3)/3) j m/s

(b) Determine the position of the particle as a function of time.

x(t) = ? m

now for part b I got x(t)=2ti + 8 (sq root t^5)j but it says this answer is incorrect. I'm not sure what I'm doing wrong? I thought I did it correctly???