Posted by **Katie** on Wednesday, September 14, 2011 at 3:03pm.

A particle starts from the origin with velocity 2i m/s at t = 0 and moves in the xy plane with a varying acceleration given by 2 (sq root t) where is in meters per second squared and t is in seconds.

(a) Determine the velocity of the particle as a function of time.

So I calculated and got

v(t) = 2i + (4 (sq root t^3)/3) j m/s

(b) Determine the position of the particle as a function of time.

x(t) = ? m

now for part b I got x(t)=2ti + 8 (sq root t^5)j but it says this answer is incorrect. I'm not sure what I'm doing wrong? I thought I did it correctly???

## Answer this Question

## Related Questions

- Physics-can anyone check my work? - A particle starts from the origin with ...
- physics - A particle starts from the origin with a velocity of 6.0 i m/s and ...
- physics - A particle moves in the xy plane with constant acceleration. At time ...
- Physics - A particle starts from the origin at t = 0 and moves along the ...
- Physics - At t=0, a particle leaves the origin with a velocity 6m/s in the ...
- Physics - A particle leaves the origin with a velocity of 7.2 m/s in the ...
- science - A particle starts from the origin with a velocity of 10 m/s and moves...
- physics - At t = 0, a particle leaves the origin with a velocity of 9 m/s in ...
- Physics - At t=0 a particle starts from rest at x=0, y=0 and moves in the xy ...
- physics - At t = 0, a particle moving in the xy plane with constant acceleration...

More Related Questions