Sunday

October 26, 2014

October 26, 2014

Posted by **Katie** on Wednesday, September 14, 2011 at 3:03pm.

(a) Determine the velocity of the particle as a function of time.

So I calculated and got

v(t) = 2i + (4 (sq root t^3)/3) j m/s

(b) Determine the position of the particle as a function of time.

x(t) = ? m

now for part b I got x(t)=2ti + 8 (sq root t^5)j but it says this answer is incorrect. I'm not sure what I'm doing wrong? I thought I did it correctly???

**Answer this Question**

**Related Questions**

Physics-can anyone check my work? - A particle starts from the origin with ...

physics - A particle starts from the origin with a velocity of 6.0 i m/s and ...

physics - A particle moves in the xy plane with constant acceleration. At time ...

Physics - A particle starts from the origin at t = 0 and moves along the ...

Physics - At t=0, a particle leaves the origin with a velocity 6m/s in the ...

Physics - A particle leaves the origin with a velocity of 7.2 m/s in the ...

physics - At t = 0, a particle leaves the origin with a velocity of 9 m/s in ...

Physics - At t=0 a particle starts from rest at x=0, y=0 and moves in the xy ...

physics - At t = 0, a particle moving in the xy plane with constant acceleration...

11th grade - a particle starts at time t=0 and moves on a number line so that ...