Wednesday

October 1, 2014

October 1, 2014

Posted by **jannaline inguito** on Wednesday, September 14, 2011 at 7:39am.

- math -
**Reiny**, Wednesday, September 14, 2011 at 10:06amlet the tank contain V units of volume

rate of first pipe = V/5 units/hr

rate of 2nd pipe = V/x units/hr

So the first pipe runs for 3 hrs

Volume = 3(V/5) = 3V/5

the second pipe runs for 4 hrs.

Volume filled by 2nd pipe = 4(V/x) = 4V/x

3V/5 + 4V/x = V

multiply by 5x

3Vx + 20V = 5xV

3x + 20 = 5x

x = 10

It would take 10 hrs using the 2nd pipe alone

**Answer this Question**

**Related Questions**

Math - A tank is filled with an intake pipe that will fill it in 5 hours and an ...

college algebra - an inlet pipe can fill a large water tank in 3 hours. an ...

Algebra - There is a water tank with a drain of an unknown size that is always ...

math - the fill pipe for a tank can fill the tank in 4 hours and the drain pipe ...

math - a tank can be filled by one pipe in 3.5 hours and emptied by another in 4...

Math - Pipes A & B can fill a storage tank in 8hours and 12 hours, respectively...

maths - a tank can be filled by one pipe in 3.5 hours and emptied by another in ...

maths - a tank can be filled by one pipe in 3.5 hours and emptied by another in ...

college algebra - water from a tank is being used for irrigation while the tank ...

Algebra - Two pipes fill a storage tank in 9 hours. If the larger pipe fills the...